Enjoy Korea with Hui: 01/10/18

[NOEPULGI]

【QUESTION NO.1】 There are three opaque boxes containing candies in front of you. One box contains only anise candies, one contains only mint candies, and the other contains a mixture of both candies. The three boxes are labeled Anise, Mint, and Mixture, but none of the labels on the boxes is correct. You can take one candy each time from each box to see what it is. How many times at least do you need to open a box and take out candy to re-put correct labels to all three boxes? (Fermat's Room)

【ANSWER NO.1】 The answer is that you only need to take one candy out of the box labeled "Mixture" to know everything.

NONE of the labels on the boxes are correct. So you can be sure that the box labeled "Mixture" does not contain a mixture of both candies—this box contains either purely anise candies or purely mint candies. Suppose the candy you take from this box is anise, then this box should be labeled "Anise". Since the box of Anise is verified, you know that the box labeled "Mint" contains neither mint candies nor anise candies, so this box can only be a box of Mixture. And therefore, the only other box left is sure to be a box of Mint.

【QUESTION NO.2】 What is the password? (Death Bell)

【ANSWER NO.2】 1320

5685 ➡ 2485 (Multiply 5 by 5 is 25)

5685 ➡ 2485 (Multiply 6 by 8 is 48)

∴

2485 ➡ 1**0 (Multiply 2 by 5 is 10)

2485 ➡ *32* (Multiply 4 by 8 is 32)

【QUESTION NO.3】

As I was going to St Ive's

I met a man with seven wives

Every wife had seven sacks

Every sack had seven cats

Every cat had seven kittens

Kittens, cats, sacks, and wives

How many were going to St Ive's? (Die Hard: With a Vengeance)

【ANSWER NO.3】 I was going to St. Ives, and I met several other people. It is NOT said that any of them were also going to St. Ives. I met them as they were going in the other direction. Only one person is going to St. Ives.

【QUESTION NO.4】 Find a secret rendezvous by breaking the cipher 'XFTUJOIPUFM607

'. (The Berlin File)

【ANSWER NO.4】 WESTIN HOTEL 607 ⬅Previous letters of the cipher alphabets

【QUESTION NO.5】 A mother is 21 years older than her son, and six years later, her age will be five times her son's age. How old is the son? (Fermat's Room)

【ANSWER NO.5】 The son has not been born yet.

Suppose the mother's age is x and the son's age is y, you can make a binary linear equation:

x – y = 21

x + 6 = 5 x (y + 6)

Solving the equation, you get y = -3/4.

-3/4 x 12 = -9, that is, the son is -9 months old, which means he's just formed in the mother's womb—the son has not been born yet.